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A positively charged particle with charge q is moving with speed V in a region of uniform magnetic field B at the instant shown in figure. An external electric field is to be applied such that the charged particle follows a straight line path. The magnitude and direction of electric field required are respectively.
A positively charged particle with charge q is moving with speed V in a region of uniform magnetic field B at the instant shown in figure- An external electric field is to be applied such that the charged particle follows a straight line path- The magnitude and direction of electric field required are respectively-
For the given instant force on the particle due to magnetic field is
F_m= qVB ĵ
So, magnetic force is acting in the positive y- axis and the particle is follo
5.4 Force on a Moving Charge in a Magnetic Field: Examples and Applications
A particle of mass m and charge q is in motion speed parallel to a long straight conductor carrying current I as shown below. yu Find magnitude and direction of electric field
In a region of crossed fields as shown, the strength of electric filed E and that of magnetic field is B. Three positively charged particles with speeds V1, V2 and V3 are
in a uniform electric field if a charge is fired in a direction different from the line of electric field then the trajectory of charge will be circle straight line parabola ellipse
Solved] . A charged particle of mass m = 4.8)(10'8 kg, moving with
A homogeneous non conducting rod RS rotates about an axis passing t
The figure shows the path of a positively charged particle 1 through a rectangular region of uniform electric field as shown in the figure. What is the direction of electric field and
A positive charge particle with charge q is moving with speed v in a region of uniform magneticfield
Lorentz force - Wikipedia
Solved] A particle of charge +q has velocity v in the positive x-dir
A charged particle (mass m and charge q) moves along X-axis with velocity V0. - Sarthaks eConnect
Two charged particles M and N enter a region of uniform magnetic field with velocities perpendicular to the field. The paths of particles are shown in figure. The possible reason is
in a uniform electric field if a charge is fired in a direction different from the line of electric field then the trajectory of charge will be circle straight line parabola ellipse
A positively charged particle, having charge q, is accelerated by a potential difference V. This particle moving along the x-axis enters a region wher - Sarthaks eConnect